7m^2-20m-32=0

Solution for 7m^2-20m-32=0 equation:

7m^2-20m-32=0

a = 7; b = -20; c = -32;
Δ = b2-4ac
Δ = -202-4·7·(-32)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-36}{2*7}=\frac{-16}{14}
=-1+1/7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+36}{2*7}=\frac{56}{14}
=4
$